Kepler 3
Astronomy Ranking Task: Kepler’s Laws – Orbital Motion Exercise #3 Description: The figure below shows a star and five orbiting planets (A – E). Note that planets A, B and C are in perfectly circular orbits. In contrast, planets D and E have more elliptical orbits. Note that the closest and farthest distances for the elliptical orbits of planets D and E happen to match the orbital. 2) The Moon orbits the Earth at a center-to-center distance of 3.86 x10 5 kilometers (3.86 x10 8 meters). Now, look at the graphic with the formulas and you will see that the 'm' in the formula stands for the mass of both orbital bodies.Usually, the mass of one is insignificant compared to the other.However, since the Moon's mass is about ⅟81 that of the Earth's, it is important that we use. Eclipse IDE Kepler SR2 Packages. Eclipse Standard 4.3.2. 201 MB; 5,489,203 DOWNLOADS; The Eclipse Platform, and all the tools needed to develop and debug it: Java and Plug-in Development Tooling, Git and CVS support, including source and developer documentation.
Click on the 'RADIUS' button, enter the time and mass, click on 'CALCULATE' and the answer is 4.2244 x107 meters or 42,244 kilometers or 26,249 miles. (This is the distance as measured from the Earth's center). r3 = (6.674x10-11 • 5.9736x1024 • 86,4002) / 39.4784 r3 = 2.976x1024 / 39.4784 r3 = 7.53922 radius = 42,244,000 meters 2) The Moon orbits the Earth at a center-to-center distance of 3.86 x105 kilometers (3.86 x108 meters). Now that you have this information, how long does it take the Moon to make one revolution around the Earth? Click on the 'TIME' button. Enter the radius and mass data. Click on 'CALCULATE' and the answer is 2,371,900 seconds or 27.453 days. t2 = (4 • π2 • 386,000,0003) / (6.674x10-11 • 6.0471x1024) t2 = 2.27x1027 / 4.0414 t2 = 5,626,000,000,000 time = 2,372,000 seconds 3) Every 152,850 seconds, Io orbits Jupiter at an average orbital radius of 421,700 kilometers (4.21x108 meters). What is Jupiter's Mass? m = (39.4784 • 421,700,0003) / (6.674x10-11 • 152,8502) m = 2.961x1027 / 1.559 mass = 1.899x1027 kilograms Numbers larger than 1,000 will be displayed in scientific notation and with the same number of significant figures specified. You may change the significant figures displayed by changing the number in the box above. Internet Explorer and most other browsers, will display the answers properly but there are a few browsers that will show no output whatsoever. If so, enter a zero in the box above. This eliminates all formatting but it is better than seeing no output at all. |
Kepler Njit 4
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